@DextereusMarcus

-b/a: Determines the sum of the roots(solutions) 
c/a: Determines the product of the roots
(sqrt(b² - 4ac))/a: Difference of the roots

@comradetirer

A good thing is to actually explain why this works

If a person really understands why something work they will alway be able to derive it

@heatheralicia5037

If anyone want to know it called vietas therom. -b/à is the sum of the solutions and c/a is the product

@jacek314

Damn, that's the first time I didn't know the easiest method right away, they didn't teach us this in school, thanks

@crazyivan5835

And, if you want to find m1 × m2 (the product), just use the formula c/a

@TickleBot32

Now how about this, by letting a and b be the roots, what is 1/a + 1/b without solving the equation

@spotlightfaithgroup1875

There's another easy way as well....2m2 dividing by 16 m2..cancel both m2....remain 2 divide by 16 = 8

@MuzHeppelwhite

since -b/2a is the midpoint in between the roots of a quadratic, it can also be called the average of the 2 roots since it lies in between with equal distance to each zero. since in the formula to find the average of n numbers we divide the sum of the numbers by n, we can remove the 2 from the midpoint formula since we are looking for the sum, not the midpoint, giving us -b/a

@dazedheart9006

Did not expect to learn something from a channel that answers SAT questions- 😭😭😭

@chance1986

It's obvious when you look at the quadratic formula, but I admit I haven't noticed this before.  Very cool!

@valett5229

what's with the roots though? i can't quite imagine x1+x2=8, x1*x2=4

@ompatel5277

Use desmos

@DanCarloDioquino

Literally my teacher thought me this amonth ago and i already forgot it poor me quite sad since my favorite subject is math

@Kenzie_SLR23_ESP26B

-b±√b²-4ac/2a

@mikko_mikko_mi

I forgot viete theorem even existed

@cracklelacquer5602

If youre looking for "im asian and i learned this in 7th grade!!" Then you have found it, imagine calling x1+x2 = -b/a and x1*x2 = c/a "shortcuts" 😒

@potatogaming7044

Wait this is actually useful

@Ben-pf9wx

Easiest solution: DESMOS

@rndmvidsxoxo

How does 8 satisfy the equation?