@joehasan5383
Why not use cosecant and set the hypotenuse equal to 'r' so that r/46=2sqrt(3)/3 r = 92sqrt(3)/3 3r = 92sqrt(3) = a*sqrt(3) a = 92
@NazarovMirkamol
This exercise that i saw in the exam on 8th march
@lynroysatube
Is your x = a(sqrt(3))/6? Doesn’t it say that the perimeter = a(sqrt(3))?
@linkmastr
46 = rt(3)×s/2, s =92/rt(3)
@BotropeGD
If only they knew how to explain
@m.ibrahim4846
Why did you put x=46×Square root three/3
@ashanasinha